A RAM has a capacity of 8192K having the word size of 16 bits and supports byte addresses only – IGNOU MCA Assignment 2015 – 16

By | August 29, 2015

MASTER OF COMPUTER APPLICATIONS

Course Code : MCS-012
Course Title : Computer Organisation and Assembly Language Programming
Assignment Number : MCA (2)/012/Assign /2014-15
Maximum Marks : 100
Weightage : 25%

A RAM has a capacity of 8192K having the word size of 16 bits and supports byte addresses only – IGNOU MCA Assignment 2015 – 16

Explanation of Concept:

A 32 × 4 RAM means that RAM has 32 words,

5 address lines (25 = 32), and 4 bit data word size.

We can represent a RAM using 2A×D,

Where

D -> Number of Data lines

The 32 × 4 RAM circuit where 5 × 32 bit decoder is used

The 4 bit data input come from input buffer

The 4-bit data output is stored in output buffer

A RAM has a capacity of 8192K having the word size of 16 bits and supports byte addresses only – IGNOU MCA Assignment 2015 – 16

A RAM has a capacity of 8192K having the word size of 16 bits and supports byte addresses only.

(i)                How many data input and output lines does this RAM need? Explain your answer.

Ans:  Data input and Data output lines are equal and of word size, Hence Ram will need 16 Data lines

(ii)             How many address lines will be needed for this RAM? Explain.

Ans:  Convert 8192K to  2× (D/2)  format supports byte addresses only

8192K/8

= (8192 * 1024) / 8

= (213 * 210) / 23

=223-3

=213

We can represent a RAM using 2A × (D/2) = 213 × (16/2) RAM Hence Address lines are 13 Address lines.