Write an 8086 assembly language program that finds the smallest and the second smallest number from a list of 10 numbers stored in memory. 7m Jun2008
To understand program for Largest or Smallest in an array in detail Please Click this link below http://cssimplified.com/computer-organisation-and-assembly-language-programming/an-assembly-program-for-finding-the-largest-number-in-array-of-10-elements
DATA SEGMENT
ARR DB 5,3,7,1,9,2,6,8,4
LEN DW $-ARR
SMALL DB ?
SECOND DB ?
DATA ENDS
CODE SEGMENT
ASSUME DS:DATA CS:CODE
START:
MOV AX,DATA
MOV DS,AX
LEA SI,ARR
MOV AL,ARR[SI]
MOV SMALL,AL
MOV CX,LEN
REPEAT1:
MOV AL,ARR[SI]
CMP SMALL,AL
JL NOCHANGE
MOV SMALL,AL
NOCHANGE:
INC SI
LOOP REPEAT1
LEA SI,ARR
MOV AL,ARR[SI]
MOV SECOND,AL
MOV CX,LEN
REPEAT2:
MOV AL,ARR[SI]
CMP SECOND,AL
JL SKIP
CMP SMALL,AL
JGE SKIP
MOV SECOND,AL
SKIP:
INC SI
LOOP REPEAT2
MOV AH,4CH
INT 21H
CODE ENDS
END START
Program code: –
[codesyntax lang=”asm”]
DATA SEGMENT
ARR DB 5,3,7,1,9,2,6,8,4
LEN DW $-ARR
SMALL DB ?
SECOND DB ?
DATA ENDS
CODE SEGMENT
ASSUME DS:DATA CS:CODE
START:
MOV AX,DATA
MOV DS,AX
LEA SI,ARR
MOV AL,ARR[SI]
MOV SMALL,AL
MOV CX,LEN
REPEAT1:
MOV AL,ARR[SI]
CMP SMALL,AL
JL NOCHANGE
MOV SMALL,AL
NOCHANGE:
INC SI
LOOP REPEAT1
LEA SI,ARR
MOV AL,ARR[SI]
MOV SECOND,AL
MOV CX,LEN
REPEAT2:
MOV AL,ARR[SI]
CMP SECOND,AL
JL SKIP
CMP SMALL,AL
JGE SKIP
MOV SECOND,AL
SKIP:
INC SI
LOOP REPEAT2
MOV AH,4CH
INT 21H
CODE ENDS
END START
[/codesyntax]
Screen shots: –
Before Execution: –
After Execution: –
2(a) Explain the process of handling an interrupt that occurs during program execution, with the help of an example. 9
Solved program can be found on this link http://cssimplified.com/computer-organisation-and-assembly-language-programming/explain-the-process-of-handling-an-interrupt-that-occurs-during-a-program-9m-jun2006